{"id":5075,"date":"2025-07-14T10:10:13","date_gmt":"2025-07-14T04:40:13","guid":{"rendered":"https:\/\/study.madeeasy.in\/?p=5075"},"modified":"2025-07-18T14:53:53","modified_gmt":"2025-07-18T09:23:53","slug":"transverse-strain","status":"publish","type":"post","link":"https:\/\/www.madeeasy.in\/study\/me\/strength-of-materials\/transverse-strain","title":{"rendered":"Transverse Strain"},"content":{"rendered":"<p style=\"text-align: justify;\">In figure shown, fibres are in compression above neutral surface or layer in longitudinal direction, so in transverse direction, fibres will elongate in transverse direction. Similarly, fibres below neutral surface are in tension in longitudinal direction, therefore, fibres will shorten in transverse direction due to Poisson\u2019s effect.<br \/>\nConsequently, a rectangular section will be transformed into a trapezoidal shape as shown:<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-5076 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2025\/07\/transverse-strain.jpg\" alt=\" Transverse Strain \" width=\"558\" height=\"308\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2025\/07\/transverse-strain.jpg 558w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2025\/07\/transverse-strain-300x166.jpg 300w\" sizes=\"auto, (max-width: 558px) 100vw, 558px\" \/><\/p>\n<p style=\"text-align: justify;\">Axial strain \u03b5x below neutral axis = y\/R (As per eq. (i))<\/p>\n<p style=\"text-align: justify;\">Therefore, transverse strain below neutral axis = \u03bdy\/R<\/p>\n<p style=\"text-align: justify;\">where \u03bd is Poisson\u2019s ratio.<\/p>\n<p style=\"text-align: justify;\">As the curvature is very small in transverse direction, therefore radius of curvature R1 is higher than radius of curvature R is longitudinal direction. The relation between R1 and R can be given as<\/p>\n<p style=\"text-align: justify;\">R1 = R\/\u03bd<\/p>\n","protected":false},"excerpt":{"rendered":"<p>In figure shown, fibres are in compression above neutral surface or layer in longitudinal direction, so in transverse direction, fibres<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1619,10],"tags":[1653,1652,1654],"class_list":["post-5075","post","type-post","status-publish","format-standard","hentry","category-strength-of-materials","category-me","tag-poissons-effect","tag-transverse-strain","tag-trapezoidal-shape"],"_links":{"self":[{"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/posts\/5075","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/comments?post=5075"}],"version-history":[{"count":0,"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/posts\/5075\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/media?parent=5075"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/categories?post=5075"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/tags?post=5075"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}