{"id":2593,"date":"2024-08-06T18:46:17","date_gmt":"2024-08-06T13:16:17","guid":{"rendered":"https:\/\/study.madeeasy.in\/?p=2593"},"modified":"2025-07-16T15:25:06","modified_gmt":"2025-07-16T09:55:06","slug":"beam-of-uniform-strength","status":"publish","type":"post","link":"https:\/\/www.madeeasy.in\/study\/ce\/strength-of-material\/beam-of-uniform-strength","title":{"rendered":"Beam of Uniform Strength"},"content":{"rendered":"<p style=\"text-align: justify;\">For an economical design, the section of the beam may be reduced towards the support, as bending moment decreases towards the supports. The beam may be designed such that at every section, the extreme fibre stress reaches the permissible stress. A beam so designed is called beam of uniform strength this <img loading=\"lazy\" decoding=\"async\" class=\"size-full wp-image-2544 alignright\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/longitudinal-1.jpg\" alt=\"Longitudinal\" width=\"275\" height=\"160\" \/> can be done by.<\/p>\n<p style=\"text-align: justify;\">(i) Uniform width varying depth<br \/>\n(ii) Uniform depth varying width<\/p>\n<p style=\"text-align: justify;\"><strong>(i) Beam of constant width:<\/strong> Let width of beam is constant throughout the span, but depth of beam is variable, such that the depth of beam at a distance x from support A is d<sub>x<\/sub> and at mid span it is equal to d.<\/p>\n<p style=\"text-align: justify;\">Section modulus at a distance x from A is given by<\/p>\n<p style=\"text-align: justify;\">Z<sub>x<\/sub> = bd<sup>2<\/sup><sub>x<\/sub>\/6<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"wp-image-2545 size-full aligncenter\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/uniform.jpg\" alt=\"Uniform\" width=\"602\" height=\"237\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/uniform.jpg 602w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/uniform-300x118.jpg 300w\" sizes=\"auto, (max-width: 602px) 100vw, 602px\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) Beam of constant depth:<\/strong> Let depth of beam is constant throughout the span but width of beam is variable such that the width of beam at a distance x from support A is b<sub>x<\/sub> and at mid span it is equal to b.<\/p>\n<p style=\"text-align: justify;\">at a distance x from A, section modulus is given by<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2546 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/beam-of-constant.jpg\" alt=\"Beam of constant\" width=\"597\" height=\"237\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/beam-of-constant.jpg 597w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/beam-of-constant-300x119.jpg 300w\" sizes=\"auto, (max-width: 597px) 100vw, 597px\" \/><\/p>\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_79_1 ez-toc-wrap-left counter-hierarchy ez-toc-counter ez-toc-light-blue ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 ' ><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.madeeasy.in\/study\/ce\/strength-of-material\/beam-of-uniform-strength\/#SHEAR-STRESS-IN-BEAMS\" >SHEAR STRESS IN BEAMS<\/a><ul class='ez-toc-list-level-4' ><li class='ez-toc-heading-level-4'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.madeeasy.in\/study\/ce\/strength-of-material\/beam-of-uniform-strength\/#Variation-of-Shear-Stress-in-Beam\" >Variation of Shear Stress in Beam<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-4'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.madeeasy.in\/study\/ce\/strength-of-material\/beam-of-uniform-strength\/#Shear-Stress-Distribution-in-Rectangular-Section\" >Shear Stress Distribution in Rectangular Section<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.madeeasy.in\/study\/ce\/strength-of-material\/beam-of-uniform-strength\/#SHEAR-CENTRE\" >SHEAR CENTRE<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.madeeasy.in\/study\/ce\/strength-of-material\/beam-of-uniform-strength\/#PLANE-STRESSES\" >PLANE STRESSES<\/a><\/li><\/ul><\/nav><\/div>\n<h3 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"SHEAR-STRESS-IN-BEAMS\"><\/span>SHEAR STRESS IN BEAMS<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><strong>Assumptions:\u00a0<\/strong><\/p>\n<ol style=\"text-align: justify;\">\n<li>Material is homogeneous and elastic.<\/li>\n<li>Material obeys Hooke\u2019s law.<\/li>\n<li>Shear stress is assumed constant along width and variation is considered along depth of section. Consider a beam of rectangular cross-section of size b \u00d7 d subjected to shear force V and two planes x<sub>1<\/sub>-x<sub>1<\/sub> and x<sub>2<\/sub>-x<sub>2<\/sub> are taken parallel to neutral axis. The direction of shear stress is assumed parallel to direction of\u00a0 shear force as shown.<\/li>\n<\/ol>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2548 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/shear-force-2.jpg\" alt=\"Shear Force\" width=\"522\" height=\"188\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/shear-force-2.jpg 522w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/shear-force-2-300x108.jpg 300w\" sizes=\"auto, (max-width: 522px) 100vw, 522px\" \/><\/p>\n<p style=\"text-align: justify;\">As we know that shear stress on one side of element is accompanied by complementary shear stress of equal magnitude acting on the perpendicular face on an element, hence equal horizontal shear stress will act on horizontal face as shown in figure (b).<br \/>\nMoreover, top and bottom fibres of beam can\u2019t have horizontal shear stress, so vertical shear stress will also vanish at top and bottom of beam.<\/p>\n<h4 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"Variation-of-Shear-Stress-in-Beam\"><\/span>Variation of Shear Stress in Beam<span class=\"ez-toc-section-end\"><\/span><\/h4>\n<p style=\"text-align: justify;\">Consider a small portion of length dx at a distance x from A between section x<sub>1<\/sub> and x<sub>2<\/sub>. Let beam is subjected to uniformly distributed load of intensity w per unit run, which produces moment M at section x<sub>1<\/sub>\u00a0and M + dM at section x<sub>2<\/sub>. The portion above NA will be in compression and portion below NA .<\/p>\n<h4 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"Shear-Stress-Distribution-in-Rectangular-Section\"><\/span>Shear Stress Distribution in Rectangular Section <img loading=\"lazy\" decoding=\"async\" class=\"alignright wp-image-2549 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/rectangular-section.jpg\" alt=\"Rectangular Section\" width=\"296\" height=\"176\" \/><span class=\"ez-toc-section-end\"><\/span><\/h4>\n<p style=\"text-align: justify;\">Consider a beam of rectangular section of width b and depth d as shown in figure.<br \/>\nShear stress for an element at a distance y above NA is given by<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"wp-image-2550 size-full aligncenter\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/shear-stress.jpg\" alt=\"Shear Stress\" width=\"638\" height=\"601\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/shear-stress.jpg 638w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/shear-stress-300x283.jpg 300w\" sizes=\"auto, (max-width: 638px) 100vw, 638px\" \/><\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2551 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/shear-stresses-.jpg\" alt=\"Shear Stresses \" width=\"520\" height=\"334\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/shear-stresses-.jpg 520w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/shear-stresses--300x193.jpg 300w\" sizes=\"auto, (max-width: 520px) 100vw, 520px\" \/><\/p>\n<p style=\"text-align: justify;\">Let, M = bending moment at x<sub>1<\/sub>-x<sub>1<\/sub><br \/>\nM + dM = Bending moment at x<sub>2<\/sub>-x<sub>2<\/sub><br \/>\nS = Shear force at x<sub>1<\/sub>-x<sub>1<\/sub><br \/>\nS + dS = Shear force at x<sub>2<\/sub>-x<sub>2<\/sub><br \/>\nConsider an elementary strip at a distance y from the NA. Let \u03c3 is bending stress at section x<sub>1<\/sub>-x<sub>1 <\/sub>at a distance y from the NA and \u03c3 + d\u03c3 is at same location at section x<sub>2<\/sub> \u2013 x<sub>2<\/sub>. By bending equation,<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2554 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/bending-stress.jpg\" alt=\"Bending stress\" width=\"486\" height=\"368\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/bending-stress.jpg 486w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/bending-stress-300x227.jpg 300w\" sizes=\"auto, (max-width: 486px) 100vw, 486px\" \/><\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2555 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/unbalance.jpg\" alt=\"Unbalance\" width=\"742\" height=\"462\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/unbalance.jpg 742w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/unbalance-300x187.jpg 300w\" sizes=\"auto, (max-width: 742px) 100vw, 742px\" \/><\/p>\n<h3 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"SHEAR-CENTRE\"><\/span>SHEAR CENTRE<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\">Consider a singly-symmetric cross-section cantilever beam of length subjected to a downward concentrated load P.<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2556 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/longitudinal-2.jpg\" alt=\"Longitudinal\" width=\"593\" height=\"146\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/longitudinal-2.jpg 593w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/longitudinal-2-300x74.jpg 300w\" sizes=\"auto, (max-width: 593px) 100vw, 593px\" \/><\/p>\n<p style=\"text-align: justify;\">Its cross section i.e. I-section with unequal flanges is shown in figure (b). Due to action of load P at any section, two stress resultant exist:<\/p>\n<p style=\"text-align: justify;\">(a) Bending moment M<sub>z<\/sub> about z axis.<br \/>\n(b) Shear force V acting in y direction.<\/p>\n<p style=\"text-align: justify;\">Bending moment M<sub>z<\/sub> is resultant of normal stresses on cross-section while shear force V is resultant of shear stress. While deriving shear stresses, we have used variation of bending moment therefore distribution of shear stresses is affected by distribution of normal stresses.<\/p>\n<p style=\"text-align: justify;\">Shear force should have its line of action passing through a point S lying on z-axis. This point S is known as shear centre and it does not coincide with centroid except in cases of doubly symmetric section.<\/p>\n<p style=\"text-align: justify;\">If the resultant of shear stress i.e. shear force does not pass through shear centre, then section will be subjected to a torsional moment in addition to shear force, it can be said that a lateral load acting on a beam will produce bending without twisting only when it passing through shear centre.<\/p>\n<h3 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"PLANE-STRESSES\"><\/span>PLANE STRESSES<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\">Consider a rectangular stress element showing normal stress and shear stress on a point in a beam subjected to both bending and shear as shown in figure (a).<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2557 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/coordinate-system.jpg\" alt=\"Coordinate system\" width=\"651\" height=\"229\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/coordinate-system.jpg 651w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/coordinate-system-300x106.jpg 300w\" sizes=\"auto, (max-width: 651px) 100vw, 651px\" \/><\/p>\n<p style=\"text-align: justify;\">Right hand face of element is taken in positive x-direction. Similarly top face of element is taken in positive y-direction.<\/p>\n<p style=\"text-align: justify;\">As, the element is subjected to stresses parallel to x and y axis, so it is a case of plane stress. As we know that shear stress on perpendicular plane is equal, therefore \u03c4<sub>xy<\/sub> = \u03c4<sub>yx<\/sub><\/p>\n<p style=\"text-align: justify;\">Now, the stress element is rotated through angle \u03b8 in anti-clockwise direction about z axis such that normals to right and top face are parallel to x\u2032 and y\u2032 axis.<\/p>\n<p style=\"text-align: justify;\">Coordinate axes x\u2032 and y\u2032 will also be at angle \u03b8 to original x and y axis.<\/p>\n<p style=\"text-align: justify;\">It is known as transformation of axes or stress transformation. Let the normal and shear stresses on rotated element are represented by \u03c3<sub>x\u2032<\/sub>, \u03c3<sub>y\u2032<\/sub> , \u03c4<sub>x\u2032y&#8217;<\/sub> and \u03c4<sub>y\u2032x&#8217;<\/sub> respectively. Note that \u03c4<sub>x\u2032y&#8217;<\/sub> and \u03c4<sub>y\u2032x&#8217;<\/sub> are also equal in magnitude.<\/p>\n<p style=\"text-align: justify;\">Stresses acting on rotated element can be expressed in terms of stress on original element using equations of static equilibrium. For this, consider a wedge shaped element as shown in figure below.<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2558 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/static-equilibrium.jpg\" alt=\"Static equilibrium\" width=\"606\" height=\"243\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/static-equilibrium.jpg 606w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/static-equilibrium-300x120.jpg 300w\" sizes=\"auto, (max-width: 606px) 100vw, 606px\" \/><\/p>\n<p style=\"text-align: justify;\">To use equations of static equilibrium, we need to rewrite stresses on rotated element in terms of forces acting on the faces of element. In, the figure, A is the area of face AB on which normal and shear stresses are acting. Then area of face BC will be A tan\u03b8 and area of face AC will be A sec\u03b8<\/p>\n<p style=\"text-align: justify;\">By equations of static equilibrium \u03a3F<sub>x<\/sub> = 0<\/p>\n<p style=\"text-align: justify;\">\u03c3<sub>x<\/sub>\u2032Asec\u03b8cos\u03b8 &#8211; \u03c4<sub>x\u2032y&#8217;<\/sub>Asec\u03b8sin\u03b8 &#8211; \u03c3<sub>x<\/sub>A \u2013 \u03c4<sub>yx<\/sub>tan\u03b8 = o<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2559 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/static-equilibrium-1.jpg\" alt=\"Static Equilibrium\" width=\"731\" height=\"273\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/static-equilibrium-1.jpg 731w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/static-equilibrium-1-300x112.jpg 300w\" sizes=\"auto, (max-width: 731px) 100vw, 731px\" \/><\/p>\n<p style=\"text-align: justify;\">The equation for \u03c3<sub>x&#8217;<\/sub> and \u03c4<sub>x\u2032y&#8217;<\/sub> are known as transformation equations.<br \/>\nNormal stress \u03c3<sub>y&#8217;<\/sub> acting on a plane normal parallel to y\u2032-axis is calculated by putting (90 + \u03b8) in place of \u03b8 in eq. (iii).<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2560 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/transformation-equations.jpg\" alt=\"Transformation Equations\" width=\"755\" height=\"281\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/transformation-equations.jpg 755w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/transformation-equations-300x112.jpg 300w\" sizes=\"auto, (max-width: 755px) 100vw, 755px\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>Special Case:<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(a) Uniaxial Stress <img loading=\"lazy\" decoding=\"async\" class=\"alignright wp-image-2561 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/biaxial-stress.jpg\" alt=\"Biaxial Stress\" width=\"245\" height=\"349\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/biaxial-stress.jpg 245w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/biaxial-stress-211x300.jpg 211w\" sizes=\"auto, (max-width: 245px) 100vw, 245px\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\">If an element xy is subjected to normal stresses in one direction only without shear stress then it is a case of uniaxial stress. Putting \u03c3<sub>y<\/sub>\u00a0and \u03c4<sub>xy<\/sub> equals to zero in eq. (iv) and (v), we get,<\/p>\n<p style=\"text-align: justify;\">Normal stress on plane rotated at angle \u03b8, \u03c3<sub>x&#8217;<\/sub> = \u03c3<sub>x<\/sub> cos2 \u03b8.<br \/>\nShear stress on plane rotated at angle \u03b8, \u03c4<sub>x\u2032y&#8217;<\/sub> = \u2013\u03c3<sub>x<\/sub> sin\u03b8 cos\u03b8.<\/p>\n<p style=\"text-align: justify;\"><strong>(b) Biaxial stress<\/strong><\/p>\n<p style=\"text-align: justify;\">If an element is subjected to normal stress in both x and y direction without shear stress, then it is a case of biaxial<br \/>\nstress.<\/p>\n<p style=\"text-align: justify;\">Putting \u03c4<sub>xy<\/sub> equals to zero in eq. (iv) and (v), we get Normal stress on plane rotated at angle \u03b8,<\/p>\n<p style=\"text-align: justify;\">\u03c3<sub>x&#8217;<\/sub> = (\u03c3<sub>x<\/sub> + \/2) + (\u03c3<sub>x<\/sub> &#8211; \u03c3<sub>y<\/sub>\/2) cos2\u03b8<\/p>\n<p style=\"text-align: justify;\">Shear stress on plane rotated at angle \u03b8, \u03c4<sub>x\u2032y&#8217;<\/sub> = (\u03c3<sub>x<\/sub> &#8211; \u03c3<sub>y<\/sub>\/2) sin2\u03b8<\/p>\n<p style=\"text-align: center;\"><a class=\"btn btn-danger\" role=\"button\" href=\"https:\/\/study.madeeasy.in\/ce\/strength-of-material\/composite-beams\/\" target=\"_blank\" rel=\"noopener\">&lt;&lt; Previous<\/a> | <a class=\"btn btn-success\" role=\"button\" href=\"https:\/\/study.madeeasy.in\/ce\/strength-of-material\/hooke-law\/\" target=\"_blank\" rel=\"noopener\"> Next &gt;&gt;<\/a><br \/>\n<strong> Must Read: <\/strong> <a href=\"https:\/\/study.madeeasy.in\/subjects\/what-is-strength-of-material\/\" target=\"_blank\" rel=\"noopener\"><strong>What is Strength of Material?<\/strong><\/a><\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>For an economical design, the section of the beam may be reduced towards the support, as bending moment decreases towards<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[685,2],"tags":[713,709,712,714],"class_list":["post-2593","post","type-post","status-publish","format-standard","hentry","category-strength-of-material","category-ce","tag-plane-stress","tag-shear-stress","tag-shear-stress-distribution","tag-uniaxial-stress"],"_links":{"self":[{"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/posts\/2593","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/comments?post=2593"}],"version-history":[{"count":0,"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/posts\/2593\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/media?parent=2593"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/categories?post=2593"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/tags?post=2593"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}