{"id":2491,"date":"2024-08-05T13:30:16","date_gmt":"2024-08-05T08:00:16","guid":{"rendered":"https:\/\/study.madeeasy.in\/?p=2491"},"modified":"2025-07-16T15:24:03","modified_gmt":"2025-07-16T09:54:03","slug":"shear-force-and-bending-moment-diagram","status":"publish","type":"post","link":"https:\/\/www.madeeasy.in\/study\/ce\/strength-of-material\/shear-force-and-bending-moment-diagram","title":{"rendered":"Shear Force and Bending Moment Diagram"},"content":{"rendered":"<p style=\"text-align: justify;\">Shear force and bending moment diagrams represent variation of shear force and bending moment along the beam. Shear force diagrams and bending moment diagrams are abbreviated as SFD and BMD respectively.<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2492 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/simply-supported.jpg\" alt=\"Simply supported\" width=\"639\" height=\"404\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/simply-supported.jpg 639w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/simply-supported-300x190.jpg 300w\" sizes=\"auto, (max-width: 639px) 100vw, 639px\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>Method of Section:\u00a0<\/strong><br \/>\n<strong>For SFD:<\/strong><br \/>\n<strong>Portion AC:<\/strong><\/p>\n<p style=\"text-align: justify;\">Consider a section x-x in portion AC at distance x from A<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2493 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/portion.jpg\" alt=\"Portion\" width=\"287\" height=\"136\" \/><\/p>\n<p style=\"text-align: justify;\">Shear force at section x-x, S<sub>x<\/sub> (x from A) = R<sub>A<\/sub> {0 \u2264 x &lt; L\/2}<\/p>\n<p style=\"text-align: justify;\">It is clear that S<sub>x<\/sub> is constant between support A and just to the left of C.<\/p>\n<p style=\"text-align: justify;\"><strong>Portion CB:<\/strong><\/p>\n<p style=\"text-align: justify;\">Again considering section x-x in portion CB at a distance x from A<br \/>\nShear force at section x-x, S<sub>x<\/sub> (x from A)= +R<sub>A<\/sub> \u2013 P = P\/2 &#8211; P = -P\/2\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 {L\/2 &lt; x \u2264 L}<br \/>\nIt is clear that Sx is constant between just right of C to the support B.<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2494 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/portion-1.jpg\" alt=\"Portion\" width=\"333\" height=\"137\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/portion-1.jpg 333w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/portion-1-300x123.jpg 300w\" sizes=\"auto, (max-width: 333px) 100vw, 333px\" \/><\/p>\n<p style=\"text-align: justify;\">Shear force in AC is +P\/2 and shear force in BC is -P\/2. Hence shear force changes sign at C.<\/p>\n<p style=\"text-align: justify;\"><strong>For BMD:\u00a0<\/strong><br \/>\n<strong>Portion AC:<\/strong><\/p>\n<p style=\"text-align: justify;\">Again considering a section x-x in portion AC at a distance x from A,<br \/>\nThen bending moment at x-x is given by<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2495 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/bending.jpg\" alt=\"Bending\" width=\"623\" height=\"152\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/bending.jpg 623w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/bending-300x73.jpg 300w\" sizes=\"auto, (max-width: 623px) 100vw, 623px\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>Portion CB:<br \/>\n<\/strong><br \/>\nAgain consider a section x-x in portion CB at a distance x from A then bending moment at x-x is given by<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2496 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/bmd.jpg\" alt=\"BMD\" width=\"623\" height=\"260\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/bmd.jpg 623w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/bmd-300x125.jpg 300w\" sizes=\"auto, (max-width: 623px) 100vw, 623px\" \/><\/p>\n<h3 style=\"text-align: justify;\">CURVE TRACING FOR SFD AND BMD<\/h3>\n<p style=\"text-align: justify;\">Suppose,\u00a0 SF\/BM = y(x) = Ax<sup>3<\/sup> + Bx<sup>2<\/sup> + Cx + D<br \/>\nthen,\u00a0 dy\/dx = 3Ax<sup>2<\/sup> + 2Bx + C<\/p>\n<p style=\"text-align: justify;\">Check dy\/dx:<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2497 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/curve-tracing.jpg\" alt=\"Curve Tracing\" width=\"623\" height=\"324\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/curve-tracing.jpg 623w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/curve-tracing-300x156.jpg 300w\" sizes=\"auto, (max-width: 623px) 100vw, 623px\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>Check for Concavity:<\/strong><\/p>\n<p style=\"text-align: justify;\">Check d<sup>2<\/sup>y\/dx<sup>2<\/sup><\/p>\n<p style=\"text-align: justify;\">If, d<sup>2<\/sup>y\/dx<sup>2<\/sup> &gt; 0 Concave up<\/p>\n<p style=\"text-align: justify;\">and d<sup>2<\/sup>y\/dx<sup>2<\/sup> &lt; 0 Concave down <sup>\u00a0<\/sup> <sup><br \/>\n<\/sup><\/p>\n<h3 style=\"text-align: justify;\">RELATIONSHIP BETWEEN LOAD, SHEAR FORCE&amp; BENDING MOMENT<\/h3>\n<h4 style=\"text-align: justify;\">When there is no concentrated load or moment<\/h4>\n<p style=\"text-align: justify;\"><strong>(i) Shear force:<\/strong> Consider a simply supported beam of length L subjected to a uniformly distributed load of intensity w kN\/m throughout its length as shown in figure (a)<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2500 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/shear-force.jpg\" alt=\"Shear force\" width=\"453\" height=\"197\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/shear-force.jpg 453w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/shear-force-300x130.jpg 300w\" sizes=\"auto, (max-width: 453px) 100vw, 453px\" \/><\/p>\n<p style=\"text-align: justify;\">Consider a small portion of length dx at a distance x from A between section x<sub>1<\/sub> and x<sub>2<\/sub>.<\/p>\n<p style=\"text-align: justify;\">Let the uniformly distributed load produces moment M and shear force V at section x1 and moment M + dM and shear force V + dV at section x<sub>2<\/sub> respectively as shown in figure (b).<\/p>\n<p style=\"text-align: justify;\">Considering equilibrium of portion dx.<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-2501\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/equilibrium.jpg\" alt=\"Equilibrium\" width=\"290\" height=\"94\" \/><\/p>\n<p style=\"text-align: justify;\">Negative sign in eq. (i) implies that loading is downward.<\/p>\n<p style=\"text-align: justify;\">To illustrate use of eq. (i), consider a cantilever beam of length L subjected to uniformly varying load whose intensity increases from zero at free end to w0 kN\/m at fixed end linearly as shown in figure (a)<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2502 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/cantilever.jpg\" alt=\"Cantilever\" width=\"617\" height=\"457\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/cantilever.jpg 617w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/cantilever-300x222.jpg 300w\" sizes=\"auto, (max-width: 617px) 100vw, 617px\" \/><\/p>\n<p style=\"text-align: justify;\">As derived earlier in eq. (i)<br \/>\nEq. (i) can also be used to calculate difference of shear force between two sections along the length of beam by finding the area of loading intensity between the sections.<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2503 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/shear-force-1.jpg\" alt=\" Shear Force\" width=\"598\" height=\"330\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/shear-force-1.jpg 598w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/shear-force-1-300x166.jpg 300w\" sizes=\"auto, (max-width: 598px) 100vw, 598px\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) Bending moment:<\/strong> Consider the equilibrium of portion dx beam element shown in figure<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2504 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/bending-moment.jpg\" alt=\"Bending Moment\" width=\"566\" height=\"188\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/bending-moment.jpg 566w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/bending-moment-300x100.jpg 300w\" sizes=\"auto, (max-width: 566px) 100vw, 566px\" \/><\/p>\n<p style=\"text-align: justify;\">To illustrate use of eq. (iv), consider the cantilever beam as shown in figure (a). At section x-x which is at distance x from free end as shown in figure (b). Loading intensity at section x-x,<\/p>\n<p style=\"text-align: justify;\">W<sub>x<\/sub> = W<sub>0<\/sub>x\/L<\/p>\n<p style=\"text-align: justify;\">To calculate bending moment, consider rotational equilibrium of right portion of section x-x as shown in figure (b).<\/p>\n<p style=\"text-align: justify;\"><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2505 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/rotational-equilibrium.jpg\" alt=\"Rotational Equilibrium\" width=\"595\" height=\"195\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/rotational-equilibrium.jpg 595w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/rotational-equilibrium-300x98.jpg 300w\" sizes=\"auto, (max-width: 595px) 100vw, 595px\" \/><\/p>\n<p style=\"text-align: justify;\">As derived earlier in eq. (iv)<br \/>\nEq. (iv) can also be used to calculate difference of bending moment between two section along length of beam by finding the area of shear force diagram between A and B.<\/p>\n<p style=\"text-align: justify;\">dM\/dx = V<br \/>\ndM = Vdx<\/p>\n<p style=\"text-align: justify;\">Integrating both sides <img loading=\"lazy\" decoding=\"async\" class=\"alignnone wp-image-2506 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/integrating.jpg\" alt=\"Integrating\" width=\"184\" height=\"36\" \/><\/p>\n<p style=\"text-align: justify;\">M<sub>B<\/sub> \u2013 M<sub>A<\/sub> = Area of shear force diagram between A and B<\/p>\n<p style=\"text-align: justify;\">For example, if we have to find out bending moment at B in beam shown in figure (a).<br \/>\nUsing eq. (v)<br \/>\nM<sub>B<\/sub> \u2013 M<sub>A<\/sub> = Area of shear force diagram between A and B<\/p>\n<p style=\"text-align: justify;\">To draw shear force diagram of beam in figure<br \/>\nV<sub>x<\/sub> = W<sub>0<\/sub>x<sup>2<\/sup>\/2L<\/p>\n<p style=\"text-align: justify;\">So, its SFD will be parabolic as shown in figure (e)<br \/>\nSFD<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"aligncenter wp-image-2507 size-full\" src=\"https:\/\/study.madeeasy.in\/wp-content\/uploads\/2024\/08\/sfd.jpg\" alt=\"SFD\" width=\"574\" height=\"265\" srcset=\"https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/sfd.jpg 574w, https:\/\/www.madeeasy.in\/study\/wp-content\/uploads\/2024\/08\/sfd-300x139.jpg 300w\" sizes=\"auto, (max-width: 574px) 100vw, 574px\" \/><\/p>\n<h3 style=\"text-align: justify;\">IMPORTANT POINTS ABOUT SHEAR FORCE DIAGRAMS AND BENDING MOMENT DIAGRAMS DERIVED FROM RELATIONSHIP<\/h3>\n<ol style=\"text-align: justify;\">\n<li>SFD is one degree higher than loading intensity diagram and BMD is one degree higher than SFD.<\/li>\n<li>Area of loading intensity diagram between two sections gives the difference of shear force at the sections.<\/li>\n<li>Area of shear force diagram between two sections gives the difference of bending moment at the section.<\/li>\n<li>Slope of shear force diagram at a section gives loading intensity at that section.<\/li>\n<li>Slope of bending moment diagram at a section gives shear force at that section.<\/li>\n<li>If at point a concentrated load or reactions acts than ordinates of SFD will change by magnitude of that load.<\/li>\n<li>If at a point concentrated moment acts, then ordinate of BMD will change by magnitude of that couple.<\/li>\n<li>If shear force changes sign at a section, then BM at that section is either maximum or minimum but inverse is not true.<\/li>\n<li>If bending moment changes sign at a section, then curvature will also change at that section. Such a point is called point of contraflexure and same point is called point of inflection on elastic curve.<\/li>\n<\/ol>\n<p style=\"text-align: justify;\"><strong>Remember:\u00a0<\/strong><\/p>\n<ol style=\"text-align: justify;\">\n<li>The distance between two adjacent point of contraflexure is known as focal length.<\/li>\n<li>The portion of beam in which shear force is constant is known as shear span.<\/li>\n<\/ol>\n<p style=\"text-align: center;\"><a class=\"btn btn-danger\" role=\"button\" href=\"https:\/\/study.madeeasy.in\/ce\/strength-of-material\/loading-diagram\/\" target=\"_blank\" rel=\"noopener\">&lt;&lt; Previous<\/a> | <a class=\"btn btn-success\" role=\"button\" href=\"https:\/\/study.madeeasy.in\/ce\/strength-of-material\/simple-bending-or-pure-bending\/\" target=\"_blank\" rel=\"noopener\"> Next &gt;&gt;<\/a><br \/>\n<strong> Must Read: <\/strong> <a href=\"https:\/\/study.madeeasy.in\/subjects\/what-is-strength-of-material\/\" target=\"_blank\" rel=\"noopener\"><strong>What is Strength of Material?<\/strong><\/a><\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Shear force and bending moment diagrams represent variation of shear force and bending moment along the beam. Shear force diagrams<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[685,2],"tags":[690,691,1172,692,1171],"class_list":["post-2491","post","type-post","status-publish","format-standard","hentry","category-strength-of-material","category-ce","tag-curve-tracing","tag-focal-length","tag-shear-force-and-bending-moment-diagram-for-simply-supported-beam","tag-shear-span","tag-what-is-shear-force-and-bending-moment"],"_links":{"self":[{"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/posts\/2491","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/comments?post=2491"}],"version-history":[{"count":0,"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/posts\/2491\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/media?parent=2491"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/categories?post=2491"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.madeeasy.in\/study\/wp-json\/wp\/v2\/tags?post=2491"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}